Given below are two statements:
Statement I: Potassium permanganate on heating at 573 K forms potassium manganate.
Statement II: Both potassium permanganate and potassium manganate are tetrahedral and paramagnetic in nature.
In the light of the above statements, choose the most appropriate answer from the options given below:

Statement I says that potassium permanganate ($$KMnO_4$$) on heating at 573 K forms potassium manganate ($$K_2MnO_4$$). The thermal decomposition of $$KMnO_4$$ proceeds as $$2KMnO_4 \xrightarrow{573\,K} K_2MnO_4 + MnO_2 + O_2$$, so Statement I is true.

Statement II claims both $$KMnO_4$$ and $$K_2MnO_4$$ are tetrahedral and paramagnetic. In $$KMnO_4$$, the permanganate ion $$MnO_4^-$$ has Mn in the +7 oxidation state with configuration $$3d^0$$, so it is tetrahedral but diamagnetic (zero unpaired electrons). In $$K_2MnO_4$$, the manganate ion $$MnO_4^{2-}$$ has Mn in the +6 state with configuration $$3d^1$$, making it tetrahedral and paramagnetic (one unpaired electron). Since $$KMnO_4$$ is diamagnetic, the claim that both are paramagnetic is false, making Statement II false.

Therefore, Statement I is true but Statement II is false, which corresponds to option (1).