In the extraction process of copper, the product obtained after carrying out the reactions
(i) $$2Cu_2S + 3O_2 \to 2Cu_2O + 2SO_2$$
(ii) $$2Cu_2O + Cu_2S \to 6Cu + SO_2$$ is called

In the extraction of copper from copper pyrites (CuFeS$$_2$$), the ore first undergoes partial roasting:

$$2\text{Cu}_2\text{S} + 3\text{O}_2 \rightarrow 2\text{Cu}_2\text{O} + 2\text{SO}_2$$

This is followed by self-reduction (Bessemerisation):

$$2\text{Cu}_2\text{O} + \text{Cu}_2\text{S} \rightarrow 6\text{Cu} + \text{SO}_2$$

In this process, Cu$$_2$$S acts as both a reducing agent and is itself oxidised. The copper obtained contains blisters (bubbles) on the surface due to the evolution of SO$$_2$$ gas during solidification. This product is called blister copper, which is about 98-99% pure copper. It is further refined by electrolysis to obtain 99.9% pure copper.

So, the answer is blister copper.