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For an adiabatic process, $$Q = 0$$ (no heat exchange with the surroundings).
From the first law of thermodynamics:
$$\Delta U = Q - W = -W$$
$$W = -\Delta U$$
For an ideal gas, the internal energy depends only on temperature:
$$\Delta U = nC_v\Delta T$$
Therefore:
$$W = -nC_v\Delta T$$
This shows that the work done in an adiabatic process depends only on the change in temperature (for a given amount of ideal gas with fixed $$C_v$$).
The answer is Option A: change in its temperature.
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