The correct IUPAC name of $$[PtBr_2(PMe_3)_2]$$ is :

We need to find the correct IUPAC name of $$[PtBr_2(PMe_3)_2]$$.

To determine this, we recall that ligands are named in alphabetical order ignoring multiplicative prefixes, with simple ligands taking prefixes like di- and tri-, while more complex ligands use bis- or tris- within parentheses; anionic ligands end in “-o” (for example, bromo for $$Br^-$$); and the metal name is followed by its oxidation state in Roman numerals.

First, the bromide anion $$Br^-$$ serves as an anionic ligand named “bromo,” and since there are two bromides, we use “dibromo.” The neutral ligand $$PMe_3$$ (trimethylphosphine) is already composite (it contains the prefix tri-), so we apply “bis” and enclose the ligand name in parentheses to obtain “bis(trimethylphosphine).” Balancing the charges via $$x + 2(-1) + 2(0) = 0$$ shows that $$x = +2$$, corresponding to platinum(II).

Next, arranging the ligand names alphabetically places “bromo” before “trimethylphosphine,” giving the name $$\text{dibromobis(trimethylphosphine)platinum(II)}$$.

The correct answer is Option (3): dibromobis(trimethylphosphine)platinum(II).