Two trains crosses each other in 14 sec when they are moving in opposite direction, and when they are moving in same direction they crosses each other in 3 min 2 sec. Find the speed of the faster train by what percent more than the speed of the slower train ?
let the speed of faster train be F m/s
And slower train be S m/s
When they move in same direction relative speed = (F -S) m/s
Time taken = 14 sec
When they move in opposite direction = (F+S) m/s
Time taken in this case = 182 sec
In both cases they are covering same distance
So , (F+S )× 14 = (F-S ) × 182
12 F = 14 S
F = $$\frac{7}{6}$$ S
so faster train is 1/6 more than the slower one which means it is 16.67% faster than the slower train.
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