Match List-I with List-II

List-I (Mixture)	List-II (Purification Process)
A. Chloroform & Aniline	I. Steam distillation
B. Benzoic acid & Naphthalene	II. Sublimation
C. Water & Aniline	III. Distillation
D. Naphthalene & Sodium chloride	IV. Crystallisation

We need to match each mixture with its appropriate purification process.

A. Chloroform & Aniline → III. Distillation

Chloroform (boiling point ≈ 61°C) and aniline (boiling point ≈ 184°C) are both liquids that are miscible with each other. Since there is a large difference in their boiling points (about 123°C), they can be easily separated by simple distillation.

B. Benzoic acid & Naphthalene → IV. Crystallisation

Both benzoic acid and naphthalene are solids. Benzoic acid is soluble in hot water and crystallises out upon cooling, while naphthalene is insoluble in water. So benzoic acid can be separated by dissolving the mixture in hot water, filtering to remove naphthalene, and then crystallising benzoic acid from the filtrate.

C. Water & Aniline → I. Steam distillation

Aniline is sparingly soluble in water and is steam volatile. Steam distillation is used to separate aniline from water, as aniline distils over with steam at a temperature below its normal boiling point.

D. Naphthalene & Sodium chloride → II. Sublimation

Naphthalene sublimes (converts directly from solid to vapor) upon heating, while sodium chloride does not. So heating the mixture causes naphthalene to sublime, leaving behind sodium chloride.

The correct matching is: A-III, B-IV, C-I, D-II

The correct answer is Option D.