Five positive charges each having charge q are placed at the vertices of a pentagon as shown in the figure. The electric potential (V) and the electric field $$(\overrightarrow{E})$$ at the center O of the pentagon due to these five positive charges are:

A

$$V= \frac{5q}{4 \pi \epsilon_{0}r}$$ and $$\overrightarrow{E} = 0$$

B

$$V= \frac{5q}{4 \pi \epsilon_{0}r}$$ and $$\overrightarrow{E} = \frac{5q}{4\pi \epsilon_{0}r^{2}} \widehat{r}$$

C

$$V= \frac{5q}{4 \pi \epsilon_{0}r}$$ and $$\overrightarrow{E} = \frac{5\sqrt{3}q}{8\pi \epsilon_{0}r^{2}} \widehat{r}$$

D

V = 0 and $$\overrightarrow{E} = 0$$