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All transistor in the N output current mirror in figure given below are matched with a finite gain $$\beta$$ and early voltage $$V_{A} = \infty$$ . The expression for load current is
$$\frac{I_{ref}}{\left(1 + \frac{(1 + N)}{\beta(\beta+1)}\right)}$$
$$\frac{I_{ref}}{\left(1 + \frac{N}{\beta(\beta+1)}\right)}$$
$$\frac{\beta I_{ref}}{\left(1 + \frac{(1 + N)}{\beta(\beta+1)}\right)}$$
$$\frac{\beta I_{ref}}{\left(1 + \frac{N}{\beta(\beta+1)}\right)}$$
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