Match List I with List II
List I   List II
A. XeF$$_4$$   I. See-saw
B. SF$$_4$$   II. Square planar
C. NH$$_4^+$$   III. Bent T-shaped
D. BrF$$_3$$   IV. Tetrahedral
Choose the correct answer from the options given below:

We determine the molecular geometry using VSEPR theory:

A. XeF$$_4$$: Xe has 8 valence electrons. With 4 F atoms, there are 4 bond pairs and 2 lone pairs (6 electron pairs total). Geometry: Square planar → II

B. SF$$_4$$: S has 6 valence electrons. With 4 F atoms, there are 4 bond pairs and 1 lone pair (5 electron pairs total). Geometry: See-saw → I

C. NH$$_4^+$$: N has 5 valence electrons, minus 1 for positive charge = 4 electrons shared with 4 H atoms. 4 bond pairs, 0 lone pairs. Geometry: Tetrahedral → IV

D. BrF$$_3$$: Br has 7 valence electrons. With 3 F atoms, there are 3 bond pairs and 2 lone pairs (5 electron pairs total). Geometry: Bent T-shaped → III

Matching: A-II, B-I, C-IV, D-III