Match List-I with List-II

List-I	List-II
A. $$\Psi_{MO} = \Psi_A - \Psi_B$$	I. Dipole moment
B. $$\mu = Q \times r$$	II. Bonding molecular orbital
C. $$\frac{N_b - N_a}{2}$$	III. Anti-bonding molecular orbital
D. $$\Psi_{MO} = \Psi_A + \Psi_B$$	IV. Bond order

We need to match items in List-I with those in List-II. For A, $$\Psi_{MO} = \Psi_A - \Psi_B$$ represents subtraction of atomic orbitals; since destructive interference yields an anti-bonding molecular orbital, A corresponds to III.

Next, for B, $$\mu = Q \times r$$ is the formula for dipole moment, where Q is the charge and r is the distance between the charges; hence, B matches with I.

Moving on to C, $$\frac{N_b - N_a}{2}$$ is the formula for bond order, where $$N_b$$ is the number of bonding electrons and $$N_a$$ is the number of anti-bonding electrons; thus, C pairs with IV.

Finally, for D, $$\Psi_{MO} = \Psi_A + \Psi_B$$ corresponds to constructive interference of atomic orbitals, giving a bonding molecular orbital, so D matches with II. From the above matchings, the correct matching is A-III, B-I, C-IV, D-II, and the correct answer is Option C.