The amount of oxygen in 3.6 moles of water is:

The molecular formula of water is H₂O. This means that one molecule of water contains two hydrogen atoms and one oxygen atom.

To find the amount of oxygen in 3.6 moles of water, we first need to determine the molar mass of water. The atomic mass of hydrogen (H) is 1 g/mol, and since there are two hydrogen atoms in water, the mass contribution from hydrogen is $$2 \times 1 = 2$$ g/mol. The atomic mass of oxygen (O) is 16 g/mol, and since there is one oxygen atom in water, its mass contribution is 16 g/mol. Therefore, the molar mass of water (H₂O) is $$2 + 16 = 18$$ g/mol.

In one mole of water, there is one mole of oxygen atoms because each water molecule has one oxygen atom. The mass of oxygen in one mole of water is equal to the mass contributed by the oxygen atom, which is 16 grams.

For 3.6 moles of water, the mass of oxygen can be found by multiplying the number of moles of water by the mass of oxygen per mole of water. So, we calculate: $$3.6 \times 16$$.

Let us break down the multiplication: $$3.6 \times 16$$ can be computed as follows. First, $$3 \times 16 = 48$$. Then, $$0.6 \times 16 = 9.6$$. Adding these together gives $$48 + 9.6 = 57.6$$ grams.

Alternatively, we can think of 3.6 as $$\frac{36}{10}$$, so $$3.6 \times 16 = \frac{36}{10} \times 16 = \frac{36 \times 16}{10}$$. Now, $$36 \times 16 = 576$$, and dividing by 10 gives $$\frac{576}{10} = 57.6$$ grams.

Therefore, the amount of oxygen in 3.6 moles of water is 57.6 grams.

Hence, the correct answer is Option A.