Question 31

Combustion of glucose $$(C_6H_{12}O_6)$$ produces $$CO_2$$ and water. The amount of oxygen (in g) required for the complete combustion of $$900 \text{ g}$$ of glucose is : [Molar mass of glucose in $$\text{gmol}^{-1} = 180$$]

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O. 900g glucose = 5 mol. O₂ needed = 30 mol = 960 g.

Option (3): 960.

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