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Radius of a certain orbit of hydrogen atom is $$8.48 \text{ Å}$$. If energy of electron in this orbit is $$E/x$$, then $$x =$$ _______ (Given $$a_0 = 0.529 \text{ Å}$$, $$E =$$ energy of electron in ground state).
Correct Answer: 16
$$r_n = n^2 a_0$$. Given $$r = 8.48$$ Å: $$n^2 = 8.48/0.529 = 16 \Rightarrow n = 4$$.
$$E_n = E/n^2 = E/16$$. So $$x = 16$$.
The answer is 16.
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