A and B can complete a task in 20 days, B and C can complete it in 30 days while C and A can do the same task together in 24 days. How many dayswill each of B and C take to complete the task individually?

(A+ B)'s 1 day's work  = $$\frac{1}{20}$$

(B + C)'s 1 day's work = $$\frac{1}{30}$$

(C + A)'s 1 day's work = $$\frac{1}{24}$$

On adding,

2(A + B + C)'s 1 day's work

= $$\frac{1}{20}$$ +$$\frac{1}{30}$$+$$\frac{1}{24}$$

 
= $$\frac{6+4+5}{120}$$= $$\frac{15}{120}$$

∴∴ (A + B + C)'s 1 day's work

= $$\frac{15}{240}$$

∴∴ B's 1 day's work

=$$\frac{15}{240}$$ - $$\frac{1}{24}$$   = $$\frac{5}{240}$$ = $$\frac{1}{48}$$




C's 1 day's work

= -$$\frac{15}{240}$$ - $$\frac{1}{20}$$= 
$$\frac{3}{240}$$ = $$\frac{1}{80}$$

so, shares = 48 and 80