JEE (Advanced) 2015 Paper-1 Question 3

Question 3

A bullet is fired vertically upwards with velocity v from the surface of a spherical planet. Whenit reaches its maximum height, its acceleration due to the planet’s gravity is $$\frac{1}{4^{th}}$$ of its value at the surface of the planet. If the escape velocity from the planet is $$v_{esc} = v\sqrt{N}$$, then the value of N is (ignore energy loss due to atmosphere)

Correct Answer: 2

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