[Solved] A bullet is fired vertically upwards with velocity v from the surface of a spherical planet. Whenit reaches its maximum height, its acceleration due to the planet’s gravity is \\frac{1}{4^{th}} of its value at the surface of the planet. If the escape velocity from the planet is v_{esc} = v\\sqrt{N}, then the value of N is (ignore energy loss due to atmosphere) - - JEE (Advanced) 2015 Paper-1