The energy dissipated by a resistor is 10 mJ in 1 s, when an electric current of 2 mA flows through it. The resistance is ________ $$\Omega$$. (Round off to the Nearest Integer)

The energy dissipated by a resistor is given by $$E = I^2 R t$$.

Given: $$E = 10$$ mJ $$= 10 \times 10^{-3}$$ J, $$I = 2$$ mA $$= 2 \times 10^{-3}$$ A, and $$t = 1$$ s.

Substituting: $$10 \times 10^{-3} = (2 \times 10^{-3})^2 \times R \times 1$$.

$$10 \times 10^{-3} = 4 \times 10^{-6} \times R$$

$$R = \frac{10 \times 10^{-3}}{4 \times 10^{-6}} = \frac{10^{-2}}{4 \times 10^{-6}} = 2500 \; \Omega$$.

The resistance is $$\boxed{2500}$$ $$\Omega$$.