An ideal transformer with purely resistive load operates at 12 kV on the primary side. It supplies electrical energy to a number of nearby houses at 120 V. The average rate of energy consumption in the houses served by the transformer is 60 kW. The value of resistive load $$(R_s)$$ required in the secondary circuit will be ______ m$$\Omega$$.

We have a transformer with primary voltage $$V_p = 12\;\text{kV} = 12000\;\text{V}$$, secondary voltage $$V_s = 120\;\text{V}$$, and average power consumption $$P = 60\;\text{kW} = 60000\;\text{W}$$.

For an ideal transformer, power is conserved. The current in the secondary circuit is

$$I_s = \frac{P}{V_s} = \frac{60000}{120} = 500\;\text{A}$$

Now the resistive load in the secondary circuit is

$$R_s = \frac{V_s}{I_s} = \frac{120}{500} = 0.24\;\Omega = 240\;\text{m}\Omega$$

Hence, the value of the resistive load is $$240$$ m$$\Omega$$. So, the answer is $$240$$.