Question 28

A 750 ml mixture contains milk and water in the respective ratio of 8 : 7. What quantity of milk can be added to mixture to get a new mixture containing milk and water in the respective ratio of 8 : 5 ?

Solution

Quantity of milk in 750 l mixture = $$\frac{8}{15} \times 750 = 400$$ ml

Quantity of water = $$750 - 400 = 350$$ ml

Let the quantity of milk to be added = $$x$$ ml

Acc to ques,

=> $$\frac{400 + x}{350} = \frac{8}{5}$$

=> $$400 + x = \frac{8}{5} \times 350 = 560$$

=> $$x = 560 - 400 = 160$$ ml

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