A jar contains a mixture of 2 liquids A and B in the ratio 4:1. If 10 liters of mixture is taken out and 10 liters of liquid B is poured into the jar, the ratio becomes 2:3. The amount of liquid A contained in the jar initially is

Let say, liquid A and B in the jar are 4k and k.

if 10 litter of mixture is taken ,then amount of A and B in the jar would be (10×4/5) and (10×1/5) or 8 litter and 2 litter respectively.

So,in the mixture A will be left 4k-8 and B will be left k-2.

Now if we add 10 litter of B ,then new amount of B will be=k-2+10=k+8.

So,

(4k-8)/(k+8)=2/3.

Or,12k-24=2k+16.

or,10k=40.

or,k=4.

So, initially amount of A was 4×4=16 litter.

D is correct choice.