On children’s day sweets were to be equally distributed amongst 300 children. But on that particular day 50 children remained absent, hence each child got one sweet extra. How many sweets were distributed?
Let there be N number of total sweets.
Let each student recieve x sweets.
Initially each student recieved x sweets i.e (N/300) = x
Afterwards, 50 students were absent.
Now, each student recieved (x+1) sweets i.e (N/300) = x+1
Solving the simultaneius equations we get,
x=5
and hence there will be total N=5*300 = 1500 sweets.
Option C is correct option.
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