Some chocolates were distributed among four friends A, B, C and D such that the respective ratio between the number of chocolates received by A and C be 7:9. B got 29 chocolates more than that of A and D got 33 chocolates more than that of C. If B got 15 chocolates more than that of C, how many chocolates did D receive?
Chocolates got by A = $$7x$$
Chocolates got by C = $$9x$$
Chocolates got by B = $$7x + 29$$
Chocolates got by D = $$9x + 33$$
Acc to ques,
=> $$(7x + 29) - (9x) = 15$$
=> $$2x = 29 - 15 = 14$$
=> $$x = 7$$
$$\therefore$$ Chocolates received by D
= $$9 \times 7 + 33 = 63 + 33 = 96$$
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