Question 25

Some chocolates were distributed among four friends A, B, C and D such that the respective ratio between the number of chocolates received by A and C be 7:9. B got 29 chocolates more than that of A and D got 33 chocolates more than that of C. If B got 15 chocolates more than that of C, how many chocolates did D receive?

Solution

Chocolates got by A = $$7x$$

Chocolates got by C = $$9x$$

Chocolates got by B = $$7x + 29$$

Chocolates got by D = $$9x + 33$$

Acc to ques,

=> $$(7x + 29) - (9x) = 15$$

=> $$2x = 29 - 15 = 14$$

=> $$x = 7$$

$$\therefore$$ Chocolates received by D

= $$9 \times 7 + 33 = 63 + 33 = 96$$

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: