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Let $$f(x) = \begin{cases} x^3 + 8, & x < 0 \\ x^2 - 4, & x \ge 0 \end{cases}$$ and $$g(x) = \begin{cases} (x - 8)^{1/3}, & x < 0 \\ (x + 4)^{1/2}, & x \ge 0 \end{cases}$$. Then the number of points, where the function $$g \circ f$$ is discontinuous, is __________.
Correct Answer: 3
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