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A block of mass 2 kg is attached with two identical springs of spring constant 20 $$\text{N m}^{-1}$$ each. The block is placed on a frictionless surface and the ends of the springs are attached to rigid supports (see figure). When the mass is displaced from its equilibrium position, it executes a simple harmonic motion. The time period of oscillation is $$\frac{\pi}{\sqrt{X}}$$ in SI unit. The value of $$X$$ is _____.
Correct Answer: 5
When block is displaced by x,
each spring contributes restoring force kx.
So net restoring force
$$F=-(k+k)x=-2kx$$
Thus effective spring constant
$$k_{\text{eff}}=2k=40\text{ N/m}$$
Given mass
m=2 kg
Time period of SHM:
$$T=2\pi\sqrt{\frac{m}{k_{\text{eff}}}}$$
$$=2\pi\sqrt{\frac{2}{40}}$$
$$=2\pi\sqrt{\frac{1}{20}}$$
$$=\frac{2\pi}{2\sqrt{5}}$$
$$=\frac{\pi}{\sqrt{5}}$$
Given
$$T=\frac{\pi}{\sqrt{\ X}}$$
so X=5
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