Question 243

A 280 m long train crosses a platform thrice its length in 6 min 40 s. What is the speed of the train?

Solution

Length of the train = 280m

Length of the platform = (280*3)m

Since the train passes the platform completely

Total disttance travelled by train = 280+(3*280) = 4*280

Time take = 6min 40s = 360+40 = 400s

Speed = 4*280/400 = 2.8 m/s

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