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Each of the six buildings, C, D, E, F, G and H has different number of floors. E has the second lowest number of floors. D has more number of floors than C and H but less than F. F does not have the maximum number of floors. H has less number of floors than both G and E. The building having second highest number of floors has 40 floors. C has 28 floors.
E has the second lowest number of floors.
D has more number of floors than C and H but less than F, => F > D > C , H
Also, F does not have the maximum number of floors, => F has second highest number of floors and D has 3rd highest.
H has less number of floors than both G and E, => H has the least floors and G has the highest floors.
Combining above statements, we get :
$$\therefore$$ G > F > D > C > E > H
Number of floors of F = 40 and C = 28
G has the highest number of floors, thus G has more floors than 40 i.e., 47 floors.
=> Ans - (E)
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