Question 23

Out of 5 cards with numbers 1, 2, 3, 4, 5, two are picked at random one after the other. What is the probability that the number in the second card is odd?

Solution

He can pick any card in $$5\times4=20$$ number of ways.

But he can pick an odd numbered card in second attempt by {$$(1,3),(1,5),(2,1),(2,3),(2,5),(3,1),(3,5),(4,1),(4,3),(4,5),(5,1),(5,3)\ .$$} :

12 different ways.

So, required probability = $$\frac{12}{20}=\frac{3}{5}.$$

D is correct choice.

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