Question 23

Out of 5 cards with numbers 1, 2, 3, 4, 5, two are picked at random one after the other. What is the probability that the number in the second card is odd?

Solution

He can pick any card in $$5\times4=20$$ number of ways.

But he can pick an odd numbered card in second attempt by {$$(1,3),(1,5),(2,1),(2,3),(2,5),(3,1),(3,5),(4,1),(4,3),(4,5),(5,1),(5,3)\ .$$} :

12 different ways.

So, required probability = $$\frac{12}{20}=\frac{3}{5}.$$

D is correct choice.

Create a FREE account and get:

Download RRB Study Material PDF
45+ RRB previous papers with solutions PDF
300+ Online RRB Tests for Free

CAT Quant Questions | CAT Quantitative Ability

CAT Averages Questions CAT Number Systems Questions CAT Venn Diagrams Questions CAT Remainders Questions CAT Averages Mixtures Alligations Questions

CAT DILR Questions | LRDI Questions For CAT

CAT Quant Based DI Questions CAT Puzzles Questions CAT Data Interpretation Basics Questions CAT DI with connected data sets Questions CAT Maxima-Minima Questions

CAT Verbal Ability Questions | VARC Questions For CAT

CAT Para Jumbles Questions CAT Odd One Out Questions CAT Miscellaneous Questions CAT Para Summary Questions CAT Reading Comprehension Questions

Follow us on

Boost your Prep!

Download App