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The average score of 3 students A, B and C is 72. When D joins them the average score of all the four becomes 70. If another student E, whose score is 4 more than that of D replaces A then the average score of B, C, D and E becomes 68. Then the score of A
Total score of A,B,C is 72×3=216.
after adding D's score total become 70×4=280.
So,D's score=280-216=64.
E's score=64+4=68.
Now ,(A+B+C+D+E)=216+64+68=348.
But total of B,C,D,E is=68×4=272.
So,A's score=348-272=76.
D is correct choice.
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