A particle is projected at an angle $$\theta$$ to the horizontal and it attains a maximum height H. The time taken by the projectile to reach the highest point, of its path is

A

$$\frac{\sqrt{H}}{g}$$

B

$$\frac{\sqrt{2H}}{g}$$

C

$$\frac{\sqrt{2H \sin \theta}}{g}$$

D

$$\frac{\sqrt{2H}}{\sin \theta}$$