Question 209
If it is possible to form only one such number with the third, the sixth and the seventh digits of the number 7394261 which is the perfect square of a two digit odd number, which of the following will be the first digit of that two digit odd number ?
Solution
Number - '7394261'
3rd, 6th and 7th digits = 9,6,1
Perfect square of a two digit odd number = $$(13)^2=169$$ and $$(31)^2=961$$
=> Ans - (E)
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