A carrier wave of amplitude 15 V is modulated by a sinusoidal base band signal of amplitude 3 V. The ratio of maximum amplitude to minimum amplitude in an amplitude modulated wave is

Given: Carrier amplitude $$A_c = 15$$ V, modulating signal amplitude $$A_m = 3$$ V.

In amplitude modulation:

Maximum amplitude = $$A_c + A_m = 15 + 3 = 18$$ V

Minimum amplitude = $$A_c - A_m = 15 - 3 = 12$$ V

Ratio = $$\frac{A_{max}}{A_{min}} = \frac{18}{12} = \frac{3}{2}$$

The correct answer is Option 2: $$\frac{3}{2}$$.

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