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Two projectiles are projected at 30$$^\circ$$ and 60$$^\circ$$ with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:
Maximum height: $$H = \frac{u^2\sin^2\theta}{2g}$$
$$\frac{H_{30}}{H_{60}} = \frac{\sin^2 30°}{\sin^2 60°} = \frac{1/4}{3/4} = \frac{1}{3}$$
The correct answer is Option 4: 1:3.
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