Question 2

The angle of projection for a projectile to have same horizontal range and maximum height is :

R = u²sin2θ/g, H = u²sin²θ/(2g). R=H: sin2θ = sin²θ/2 → 2sinθcosθ = sin²θ/2 → 4cosθ = sinθ → tanθ = 4.

Option (1): tan⁻¹(4).

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