Question 2

# A 5 kg object is raised through a height of 4 m. The work done by the force of gravityacting on the object is $$(take g =10m/s^{2})$$:

Solution

The correct option is D.

Work done = $$-mgh$$ = - 5 x 4 x 10 = - 200J

Note:- work done will be negative as displacement and force of gravity are in the opposite direction.