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Question 2
A 5 kg object is raised through a height of 4 m. The work done by the force of gravity
acting on the object is $$(take g =10m/s^{2})$$:
Solution
The correct option is D.
Work done = $$-mgh$$ = - 5 x 4 x 10 = - 200J
Note:- work done will be negative as displacement and force of gravity are in the opposite direction.
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