Question 195

Two pieces of can full a tank in 10h and 16 h respectively. A third pipe can empty the tank in 32 h. If all the three pipes function simultaneously, then in how much time the tank will be full?? (in h)

Solution

If all the pipes are working together, then part of the tank filled in one hr will be = $$\frac{1}{10} + \frac{1}{16} - \frac{1}{32} = \frac{21}{160}$$

Hence, it will take $$\frac{160}{21}$$ hr to fill the complete tank

So answer will be B

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Two pieces of can full a tank in 10h and 16 h respectively. A third pipe can empty the tank in 32 h. If all the three pipes function simultaneously, then in how much time the tank will be full?? (in h)

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