Question 19

The present population of a city P is thrice the present population of city Q. Two years hence, the population of city Q will be 18513. If the rate of growth of population of city Q is 10% per annum, what is the present population of city P ?

Solution

Let the present population of city Q = $$x$$

=> $$x (1 + \frac{10}{100})^2 = 18513$$

=> $$x \times \frac{121}{100} = 18513$$

=> $$x = 15300$$

$$\therefore$$ Present population of city P = 15300 * 3 = 45900


Create a FREE account and get:

  • Banking Quant Shortcuts PDF
  • Free Banking Study Material - (15000 Questions)
  • 135+ Banking previous papers with solutions PDF
  • 100+ Online Tests for Free

cracku

Boost your Prep!

Download App