The present population of a city P is thrice the present population of city Q. Two years hence, the population of city Q will be 18513. If the rate of growth of population of city Q is 10% per annum, what is the present population of city P ?
Let the present population of city Q = $$x$$
=> $$x (1 + \frac{10}{100})^2 = 18513$$
=> $$x \times \frac{121}{100} = 18513$$
=> $$x = 15300$$
$$\therefore$$ Present population of city P = 15300 * 3 = 45900
Create a FREE account and get:
