Consider the lines
$$L_1:\frac{x+1}{3} = \frac{y+2}{1} = \frac{z+1}{2}$$
$$L_1:\frac{x-2}{1} = \frac{y+2}{2} = \frac{z-3}{3}$$
The distance of the point (1,1, 1) from the plane passing through the point (-1, -2, -1) and whose normalis perpendicularto both the lines $$L_1$$ and $$L_2$$ is
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