Join WhatsApp Icon JEE WhatsApp Group
Question 19

Let $$f(x) = \begin{cases} \frac{1}{3}, & x \le \frac{\pi}{2} \\ \frac{b(1 - \sin x)}{(\pi - 2x)^2}, & x > \frac{\pi}{2} \end{cases}$$. If $$f$$ is continuous at $$x = \pi/2$$, then the value of $$\int_0^{3b-6} |x^2 + 2x - 3| \, dx$$ is :

Create a FREE account and get:

  • Free JEE Mains Previous Papers PDF
  • Take JEE Mains paper tests

50,000+ JEE Students Trusted Our Score Calculator

Predict your JEE Main percentile, rank & performance in seconds

Ask AI

Ask our AI anything

AI can make mistakes. Please verify important information.