A bag contains coins of denomination ₹ 1, ₹ 5 and ₹ 10. Assuming there are equal number of ₹ 1, ₹ 5 and ₹ 10 coins, what will the total number of coins in the bag be if the total money is ₹ 368?

Given that a boy has 5 rupee coins , 10 rupee coins and 1 rupee coins.

Let the number of 5 rupee coins be x , and number of 10 rupee coins be y and number of 1 rupee coins be z.

Total amount is 368 rupees.

Hence, 5x + 2y + 1z = 368

Now our aim is to find the values of x , y , z such that the above equation satisfies.

Given that , the 5 rupee coins , 2 rupee coins and 1 rupee coins are in the ratio of 1:1:1

Hence x is a multiple of 1 , y is a multiple of 1 and z is a multiple of 1

Therefore , x = a , y = a , z = a , where a is any natural number.

Substitute the values of x , y and z in our first equation.

5a + `10a + 1a = 368

16a = 368
a=23

3a=69