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Question 186
12 yr ago the ratio between the ages of A and B was 3:4 respectively. The present age of A is $$3\frac{3}{4}$$ times of C’s present age. If C’s present age is 10 yr, then what is B’s present age?
Solution
$$\frac{a-12}{b-12} = \frac{3}{4}$$
$$\frac{a}{c}$$ = $$\frac{15}{4}$$
c = 10 => a = 37.5
=> b = 46 years
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