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When $$ax^{2} + bx + 2$$ is divided by $$x-1$$ and $$x+2$$ if the remainders are 6 and 0 respectively, then the quadratic equation formed with 'a' and 'b' as its roots is
$$x^{2} + 2x - 3=0$$
$$x^{2} - 4x + 3=0$$
$$x^{2} + 4x + 3=0$$
$$x^{2} - 5x + 6=0$$
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