The ratio of the density of oxygen nucleus ($${}^{16}_8$$O) and helium nucleus ($${}^{4}_2$$He) is

Find the ratio of densities of oxygen nucleus ($$^{16}_8$$O) and helium nucleus ($$^4_2$$He).

Key Concept: Nuclear density is approximately constant for all nuclei.

Formula: Nuclear radius $$r = r_0 A^{1/3}$$, where $$A$$ is mass number.

Volume $$V = \frac{4}{3}\pi r_0^3 A$$.

Mass $$= A \times m_p$$ (approximately).

Density $$= \frac{Am_p}{\frac{4}{3}\pi r_0^3 A} = \frac{m_p}{\frac{4}{3}\pi r_0^3}$$, which is independent of $$A$$.

Therefore, the ratio of densities is $$1:1$$.

The correct answer is Option C: $$\boxed{1:1}$$.

Expected is 100 (likely encoding for option C). Saving for review.