Let ABCD be a tetrahedron such that the edges AB, AC and AD are mutually perpendicular. Let the areas of the triangles ABC, ACD and ADB be 5, 6 and 7 square units respectively. Then the area (in square units) of the $$\triangle BCD$$ is equal to:

A

$$\sqrt{340}$$

B

12

C

$$\sqrt{110}$$

D

$$7\sqrt{3}$$