For the given logic gates combination, the correct truth table will be

Solution :

From the circuit :

Top AND gate gets inputs :

$$\overline{A} \text{ and } B$$

So, output of top AND gate is :

$$\overline{A}B$$

Bottom AND gate gets inputs :

$$A \text{ and } \overline{B}$$

So, output of bottom AND gate is :

$$A\overline{B}$$

These outputs are given to OR gate.

Therefore,

$$X = \overline{A}B + A\overline{B}$$

This is XOR operation.

Truth table :

| A | B | X |

|---|---|---|

| 0 | 0 | 0 |

| 0 | 1 | 1 |

| 1 | 0 | 1 |

| 1 | 1 | 0 |