JEE WhatsApp Group
Sign in
Please select an account to continue using cracku.in
↓ →
JEE WhatsApp Group
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
For a nucleus $$^A_Z X$$ having mass number A and atomic number Z
A. The surface energy per nucleon $$(b_s) = -a_1 A^{2/3}$$.
B. The Coulomb contribution to the binding energy $$b_c = -a_2 \dfrac{Z(Z-1)}{A^{1/3}}$$.
C. The volume energy $$b_v = a_3 A$$
D. Decrease in the binding energy is proportional to surface area.
E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons.
($$a_1, a_2$$ and $$a_3$$ are constants)
Choose the most appropriate answer from the options given below:
$$E_v = a_3 A$$
$$E_s = -a_1 A^{2/3}$$
$$E_c = -a_2 \frac{Z(Z-1)}{A^{1/3}}$$
$$\text{Statement A is wrong: } b_s \text{ is total surface energy } (\propto A^{2/3})\text{, not per nucleon.}$$
$$\text{Statement B is correct: } b_c = -a_2 \frac{Z(Z-1)}{A^{1/3}}$$
$$\text{Statement C is correct: } b_v = a_3 A$$
$$\text{Statement D is correct: } E_s \propto \text{surface area } (4\pi R^2 \propto A^{2/3})$$
$$\text{Statement E is wrong: Surface nucleons interact with fewer neighbors than interior ones.}$$
Create a FREE account and get:
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
