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Solution
We know that $$60^2 = 3600$$. So, let us calculate $$59^2 = 3481$$
Hence, $$3481 < 3500 < 3600$$ and so, the square which is greater than 3500 and closest to it is 3600.
Hence, the least number that must be added to $$3500$$ to make it a perfect square is $$3600-3500 = 100$$
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