Question 176

The average of four consecutive even numbers P. Q. R and S respectivelv is 55. What is the product of Q and S ?

Solution

Let P = n-3

then, Q = n-1, R = n+1, S= n+3 (since they are consecutive even numbers

Sum of the elements = 4n = $$ 4 \times 55$$ (since given that average is 55)

hence, n = 55

Q = n-1 = 54 and S = n+3 = 58

product = $$ 54 \times 58 $$

=3132

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