The average of four consecutive even numbers P. Q. R and S respectivelv is 55. What is the product of Q and S ?
Let P = n-3
then, Q = n-1, R = n+1, S= n+3 (since they are consecutive even numbers
Sum of the elements = 4n = $$ 4 \times 55$$ (since given that average is 55)
hence, n = 55
Q = n-1 = 54 and S = n+3 = 58
product = $$ 54 \times 58 $$
=3132
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