Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
If the measurement errors in all the independent quantities are known, then it is possible to determine the error in any dependent quantity. This is done by the use of series expansion and truncating the expansion at the first power of the error. For example, consider the relation $$Z = \frac{x}{y}$$. If the errors in x, y and z are $$\triangle x, \triangle y$$ and $$\triangle z$$ respectively, then $$Z \pm \triangle Z = \frac{x \pm \triangle x}{y \pm \triangle y}=\frac{x}{y} \left(1 \pm \frac{\triangle x}{x} \right) \left(1 \pm \frac{\triangle y}{y} \right)^{-1}$$.Β The series expansion for $$\left(1 \pm \frac{\triangle y}{y}\right)^{-1}$$, to to first power in $$\frac{\triangle y}{y}$$, is $$1 \mp \left(\frac{\triangle y}{y}\right)$$ The relative errors in independent variables are always added. So the error in z will beΒ $$\triangle z = z(\frac{\triangle x}{x} + \frac{\triangle y}{y})$$. The above derivation makes the assumption that $$\frac{\triangle x}{x} \ll 1, \frac{\triangle y}{y} \ll 1$$.Therefore, the higher powers of these quantities are neglected.
Consider the ratio $$\gamma=\frac{(1-a)}{(1+a)}$$ to be determined by measuring a dimensionless quantity π. If the error in the measurement of π is $$\triangle a(\frac{\triangle a}{a} \ll 1)$$,then what is the error $$\triangle π $$ in determining r?
Create a FREE account and get:
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.