Consider a planet whose mass and radius are both twice the mass and radius of Earth. The
acceleration due to gravity on the surface of the planetis n times that on Earth. The value of n is:
The correct option is C.
The acceleration due to gravity on earth $$g=\frac{GM}{r^{2}}$$ , where M = mass of the earth and r= radius of earth
Now, $$M’=2M$$ and $$r’=2r$$
$$g’=\frac{G(2M)}{(4r^{2})}$$=$$\frac{1}{2}g$$
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