If ABCD is a cyclic quadrilateral in which $$\angle$$ABC = $$47^\circ$$  and  $$\angle$$BCD = $$97^\circ$$  then  $$\angle$$ADC - $$\angle$$BAD =

Sum of the opposite angles of cyclic quadrilateral is 180 degrees

$$\angle$$ABC + $$\angle$$ADC = $$180^\circ$$

$$\Rightarrow$$ $$47^\circ$$ + $$\angle$$ADC = $$180^\circ$$

$$\Rightarrow$$  $$\angle$$ADC = $$133^\circ$$

$$\angle$$BCD + $$\angle$$BAD = $$180^\circ$$

$$\Rightarrow$$ $$97^\circ$$ + $$\angle$$BAD = $$180^\circ$$

$$\Rightarrow$$ $$\angle$$BAD = $$83^\circ$$

$$\therefore\ $$ $$\angle$$ADC - $$\angle$$BAD = $$133^\circ$$ - $$83^\circ$$ = $$50^\circ$$

Hence, the correct answer is Option B