Given that $$1 + \frac{1}{2^2} + \frac{1}{3^2} + \frac{1}{4^2} + ...... = \frac{\pi^2}{6}$$, the value of $$1 + \frac{1}{3^2} + \frac{1}{5^2} + \frac{1}{7^2} + ......$$ is

A

$$\frac{\pi^2}{6} - 1$$

B

$$\frac{\pi}{6}$$

C

$$\frac{\pi^2}{12}$$

D

$$\frac{\pi^2}{8}$$